Identify the strongest base from the followin | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In the case of lanthanides,as the atomic number $(Z)$ increases,the ionic size decreases due to lanthanide contraction. As the size of the $Ln^{3+

Vedclass · Accepted Answer

$La(OH)_3$

Vedclass · Answer

(B) In the case of lanthanides,as the atomic number $(Z)$ increases,the ionic size decreases due to lanthanide contraction. As the size of the $Ln^{3+}$ ion decreases,the covalent character of the $Ln-OH$ bond increases,which leads to a decrease in basic strength. Therefore,the basic character follows the order: $La(OH)_3 > Pr(OH)_3 > Sm(OH)_3 > Lu(OH)_3$. Thus,$La(OH)_3$ is the strongest base.

Identify the strongest base from the following.

Similar Questions

Elements in which $4f$ orbitals are progressively filled are called as

Discuss the trends in oxidation states shown by actinoids.

What is lanthanoid contraction? What are the consequences of lanthanoid contraction?

The electronic configuration for Neodymium is: (Atomic Number for Neodymium $60$)

The correct basicity order of the following lanthanide ions is

Vedclass Test Series

Exam Paper Generator

Online Exam Module