Identify the substrate 'A' in the following r | vedclass

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(A) $1$. The reaction is the Hofmann elimination of a quaternary ammonium salt.$2$. Step $(i)$ involves the exchange of the halide ion with the hydrox

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$CH_3CH_2N^+(CH_3)_3 X^-$

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(A) $1$. The reaction is the Hofmann elimination of a quaternary ammonium salt.$2$. Step $(i)$ involves the exchange of the halide ion with the hydroxide ion using moist $Ag_2O$ $(AgOH)$, forming the quaternary ammonium hydroxide: $A + AgOH \rightarrow [CH_3CH_2N^+(CH_3)_3]OH^- + AgX$.$3$. Step (ii) is the thermal decomposition (Hofmann elimination) of the hydroxide. According to the Hofmann rule, the less substituted alkene is formed. Here, $CH_2=CH_2$ (ethene) is formed from the ethyl group, and the remaining part is $CH_3CH_2N(CH_3)_2$.$4$. Thus, the substrate '$A$' must be $Ethyltrimethylammonium$ halide.

Identify the substrate '$A$' in the following reaction: $A \xrightarrow[ii) \Delta]{i) \text{Moist } Ag_2O} CH_3CH_2N(CH_3)_2 + CH_2 = CH_2 + H_2O$

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