Identify the type of hybridization involved i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In the hexaamminecobalt$(III)$ complex ion,$[Co(NH_3)_6]^{3+}$,the central metal ion is $Co^{3+}$.The electronic configuration of $Co$ $(Z=27)$ is

Vedclass · Accepted Answer

$d^2sp^3$

Vedclass · Answer

(B) In the hexaamminecobalt$(III)$ complex ion,$[Co(NH_3)_6]^{3+}$,the central metal ion is $Co^{3+}$.The electronic configuration of $Co$ $(Z=27)$ is $[Ar] 3d^7 4s^2$.The electronic configuration of $Co^{3+}$ is $[Ar] 3d^6$.Since $NH_3$ is a strong field ligand,it causes pairing of electrons in the $3d$ orbitals.This results in two empty $3d$ orbitals,one $4s$ orbital,and three $4p$ orbitals,which undergo $d^2sp^3$ hybridization to form an octahedral complex.

List-$I$ (Complex)	List-$II$ (Hybridization)
$A. Ni(CO)_4$	$I. sp^3d^2$
$B. [Ni(CN)_4]^{2-}$	$II. d^2sp^3$
$C. [Co(NH_3)_6]^{3+}$	$III. dsp^2$
$D. [CoF_6]^{3-}$	$IV. sp^3$

Identify the type of hybridization involved in the hexaamminecobalt$(III)$ complex ion.

Similar Questions

Match the complexes in List-$I$ with their hybridization in List-$II$.
List-$I$ (Complex) List-$II$ (Hybridization)
$A. Ni(CO)_4$ $I. sp^3d^2$
$B. [Ni(CN)_4]^{2-}$ $II. d^2sp^3$
$C. [Co(NH_3)_6]^{3+}$ $III. dsp^2$
$D. [CoF_6]^{3-}$ $IV. sp^3$

What is the type of magnetic behavior and geometry respectively in Cuproammonium sulphate (Atomic no. of $Cu=29$)?

$[Cr(H_2O)_6]Cl_3$ $(At. \text{ } no. \text{ } of \text{ } Cr = 24)$ has a magnetic moment of $3.83 \text{ } B.M.$ The correct distribution of $3d$ electrons in the chromium of the complex is

How many different types of $O-B-O$ angles are there in sodium peroxoborate?

The hybridised orbitals used by silver in the complex $[Ag(NH_3)_2]^+$ are of the type

Vedclass Test Series

Exam Paper Generator

Online Exam Module