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Question

(C) The speed of electromagnetic waves in a vacuum is given by $c = \frac{1}{\sqrt{\mu_0 \varepsilon_0}}$.In a medium with absolute permeability $\mu$

Vedclass · Accepted Answer

$v = \frac{c}{\sqrt{\mu_r K}}$

Vedclass · Answer

(C) The speed of electromagnetic waves in a vacuum is given by $c = \frac{1}{\sqrt{\mu_0 \varepsilon_0}}$.In a medium with absolute permeability $\mu$ and absolute permittivity $\varepsilon$,the speed is $v = \frac{1}{\sqrt{\mu \varepsilon}}$.We know that $\mu = \mu_0 \mu_r$ and $\varepsilon = \varepsilon_0 K$,where $\mu_r$ is the relative permeability and $K$ is the dielectric constant (relative permittivity).Substituting these into the expression for $v$,we get $v = \frac{1}{\sqrt{(\mu_0 \mu_r)(\varepsilon_0 K)}} = \frac{1}{\sqrt{\mu_0 \varepsilon_0} \sqrt{\mu_r K}}$.Since $c = \frac{1}{\sqrt{\mu_0 \varepsilon_0}}$,we can write $v = \frac{c}{\sqrt{\mu_r K}}$.

If $c$ is the speed of electromagnetic waves in vacuum,its speed in a medium of dielectric constant $K$ and relative permeability $\mu_r$ is

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