If $0.01 \, M$ solution of an electrolyte has a resistance of $40 \, \Omega$ in a cell having a cell constant of $0.4 \, cm^{-1}$,then its molar conductance in $ohm^{-1} \, cm^2 \, mol^{-1}$ will be :-

  • A
    $10^4$
  • B
    $10^3$
  • C
    $10^2$
  • D
    $10$

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Similar Questions

Molar ionic conductivities of a divalent cation and a divalent anion are $57 \ S \ cm^2 \ mol^{-1}$ and $73 \ S \ cm^2 \ mol^{-1}$ respectively. The molar conductivity of a solution of an electrolyte containing these ions will be:

Explain the effect of change in concentration on the conductivity of a solution.

The molar conductivity of $KCl$ solutions at different concentrations at $298 \ K$ is given below:
$c / mol \ L^{-1}$$\Lambda_m / S \ cm^2 \ mol^{-1}$
$0.000198$$148.61$
$0.000309$$148.29$
$0.000521$$147.81$
$0.000989$$147.09$

Show that a plot of $\Lambda_m$ versus $c^{1/2}$ is a straight line. Determine the values of $\Lambda_m^o$ and $A$ for $KCl$.

The specific conductivity of a saturated solution of silver chloride is $2 \times 10^{-6} \, S \, cm^{-1}$ at $25 \, ^oC$. What will be the solubility of silver chloride at $25 \, ^oC$ if molar conductivities at infinite dilution of $Ag^{+}$ and $Cl^{-}$ ions are $60$ and $80 \, S \, cm^2 \, mol^{-1}$ respectively?

How is the cell constant determined?

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