If p_x and p_y orbitals participate in sp^2 h | vedclass

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(C) In $SO_3$,the sulphur atom undergoes $sp^2$ hybridisation. The orbitals involved in $sp^2$ hybridisation are $s$,$p_x$,and $p_y$. Since the molecu

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$d_{xz}, d_{yz}$

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(C) In $SO_3$,the sulphur atom undergoes $sp^2$ hybridisation. The orbitals involved in $sp^2$ hybridisation are $s$,$p_x$,and $p_y$. Since the molecule is planar (lying in the $xy$-plane),the $p_z$ orbital remains unhybridised and is involved in $p\pi-p\pi$ bonding. To form $p\pi-d\pi$ bonds,the $d$ orbitals must have the correct symmetry to overlap with the remaining $p$ orbitals of oxygen. Given the $sp^2$ hybridisation uses $p_x$ and $p_y$,the $d$ orbitals that can participate in $\pi$-bonding with the $p_z$ orbital of oxygen are $d_{xz}$ and $d_{yz}$.

If $p_x$ and $p_y$ orbitals participate in $sp^2$ hybridisation of the sulphur atom in $SO_3$,then the $d$ orbitals which are used in $p\pi-d\pi$ bonds are

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