If $\lambda$ is the ratio of the roots of the quadratic equation in $x$,$3m^2x^2 + m(m - 4)x + 2 = 0$,then the least value of $m$ for which $\lambda + \frac{1}{\lambda} = 1$ is:

  • A
    $2 - \sqrt{3}$
  • B
    $4 - 3\sqrt{2}$
  • C
    $-2 + \sqrt{2}$
  • D
    $4 - 2\sqrt{3}$

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