If 5% of the energy supplied to a bulb is irr | vedclass

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(A) The power supplied to the bulb is $P = 100 \, W = 100 \, J/s$.Energy radiated as visible light per second is $E = 5\% 	ext{ of } 100 \, J/s = \fr

Vedclass · Accepted Answer

$1.4 	imes 10^{19}$

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(A) The power supplied to the bulb is $P = 100 \, W = 100 \, J/s$.Energy radiated as visible light per second is $E = 5\% 	ext{ of } 100 \, J/s = \frac{5}{100} 	imes 100 = 5 \, J/s$.The energy of a single photon is given by $E_{photon} = \frac{hc}{\lambda}$.Given $\lambda = 5.6 	imes 10^{-5} \, cm = 5.6 	imes 10^{-7} \, m$,$h = 6.6 	imes 10^{-34} \, J \cdot s$,and $c = 3 	imes 10^8 \, m/s$.Let $n$ be the number of photons emitted per second.Then $n 	imes E_{photon} = 5 \, J/s$.$n = \frac{5 	imes \lambda}{hc} = \frac{5 	imes 5.6 	imes 10^{-7}}{(6.6 	imes 10^{-34}) 	imes (3 	imes 10^8)}$.$n = \frac{28 	imes 10^{-7}}{19.8 	imes 10^{-26}} \approx 1.414 	imes 10^{19} \approx 1.4 	imes 10^{19}$ photons per second.

If $5\%$ of the energy supplied to a bulb is irradiated as visible light,how many quanta are emitted per second by a $100 \, W$ lamp? Assume the wavelength of visible light is $5.6 \times 10^{-5} \, cm$.

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