If $\vec{A}$ and $\vec{B}$ are two non-zero vectors such that $|\vec{A} + \vec{B}| = \frac{|\vec{A} - \vec{B}|}{2}$ and $|\vec{A}| = 2|\vec{B}|$,then the angle between $\vec{A}$ and $\vec{B}$ is

If $A$ and $B$ are two vectors such that $|A + B| = 2|A - B|$,the angle between vectors $A$ and $B$ is:

Two vectors $\overrightarrow{A}$ and $\overrightarrow{B}$ lie in a plane,and another vector $\overrightarrow{C}$ lies outside this plane. Then,the resultant of these three vectors,i.e.,$\overrightarrow{A} + \overrightarrow{B} + \overrightarrow{C}$:

What is the position vector of a particle located at $(3, 2, 5)$?

$A$ vector has a magnitude the same as that of $\overrightarrow{A} = 3 \hat{i} + 4 \hat{j}$ and is parallel to $\overrightarrow{B} = 4 \hat{i} + 3 \hat{j}$. The $x$ and $y$ components of this vector in the first quadrant are $X$ and $3$ respectively,where $X = $ . . . . . . .

Find the unit vector in the direction of $2\hat{i} + 3\hat{j} + 4\hat{k}$.