If AgI crystallises in zinc blende structure | vedclass

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(B) In a zinc blende $(ZnS)$ structure,the anions $(I^{-})$ form a face-centered cubic $(fcc)$ lattice.Each unit cell contains $4$ anions $(I^{-})$.Th

Vedclass · Accepted Answer

$50$

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(B) In a zinc blende $(ZnS)$ structure,the anions $(I^{-})$ form a face-centered cubic $(fcc)$ lattice.Each unit cell contains $4$ anions $(I^{-})$.The number of tetrahedral voids in an $fcc$ lattice is $2 	imes$ (number of atoms) = $2 	imes 4 = 8$.Since the formula of the compound is $AgI$,the ratio of $Ag^{+}$ to $I^{-}$ is $1:1$.Therefore,there are $4$ $Ag^{+}$ ions in the unit cell.The fraction of tetrahedral voids occupied by $Ag^{+}$ ions is $\frac{4}{8} = 0.5$,which is $50\%$.

If $AgI$ crystallises in zinc blende structure with $I^{-}$ ions at lattice points,what fraction of tetrahedral voids is occupied by $Ag^{+}$ ions? ............ $\%$

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