If $10$ different balls are to be placed in $4$ distinct boxes at random,then the probability that two of these boxes contain exactly $2$ and $3$ balls is

  • A
    $\frac{945}{2^{11}}$
  • B
    $\frac{965}{2^{11}}$
  • C
    $\frac{945}{2^{10}}$
  • D
    $\frac{965}{2^{10}}$

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