If $A=\{3, 5, 7, 9, 11\}, B=\{7, 9, 11, 13\}, C=\{11, 13, 15\}$ and $D=\{15, 17\}$; find $A \cap (B \cup D)$.
(N/A) First,find the union of sets $B$ and $D$:
$B \cup D = \{7, 9, 11, 13\} \cup \{15, 17\} = \{7, 9, 11, 13, 15, 17\}$.
Next,find the intersection of set $A$ with the result:
$A \cap (B \cup D) = \{3, 5, 7, 9, 11\} \cap \{7, 9, 11, 13, 15, 17\}$.
The common elements are $\{7, 9, 11\}$.
Therefore,$A \cap (B \cup D) = \{7, 9, 11\}$.
$B \cup D = \{7, 9, 11, 13\} \cup \{15, 17\} = \{7, 9, 11, 13, 15, 17\}$.
Next,find the intersection of set $A$ with the result:
$A \cap (B \cup D) = \{3, 5, 7, 9, 11\} \cap \{7, 9, 11, 13, 15, 17\}$.
The common elements are $\{7, 9, 11\}$.
Therefore,$A \cap (B \cup D) = \{7, 9, 11\}$.
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