(A) Given the inequality $|x+2| \leq 8$. By the property of absolute value inequalities,$|u| \leq a$ implies $-a \leq u \leq a$. Applying this to the

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(A) Given the inequality $|x+2| \leq 8$. By the property of absolute value inequalities,$|u| \leq a$ implies $-a \leq u \leq a$. Applying this to the given expression: $-8 \leq x+2 \leq 8$. Subtract $2$ from all parts of the inequality: $-8 - 2 \leq x \leq 8 - 2$. $-10 \leq x \leq 6$. Therefore,$x \in [-10, 6]$.