If 50 % of (x-y) = 30 % of (x+y),then what pe | vedclass

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(B) Given that $\frac{50}{100}(x-y) = \frac{30}{100}(x+y)$.Simplifying the equation: $50(x-y) = 30(x+y)$.Dividing by $10$: $5(x-y) = 3(x+y)$.Expanding

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$25$

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(B) Given that $\frac{50}{100}(x-y) = \frac{30}{100}(x+y)$.Simplifying the equation: $50(x-y) = 30(x+y)$.Dividing by $10$: $5(x-y) = 3(x+y)$.Expanding the terms: $5x - 5y = 3x + 3y$.Rearranging the terms to solve for $x$ and $y$: $5x - 3x = 3y + 5y$,which gives $2x = 8y$.Therefore,$\frac{y}{x} = \frac{2}{8} = \frac{1}{4}$.To find the percentage of $x$ that $y$ represents,we calculate $\frac{y}{x} 	imes 100 = \frac{1}{4} 	imes 100 = 25 \%$.

If $50 \%$ of $(x-y) = 30 \%$ of $(x+y)$,then what percent of $x$ is $y$?

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