If x: y = 2: 1, then (x^{2} - y^{2}) : (x^{2} | vedclass

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(A) Given the ratio $x : y = 2 : 1$,we can write this as $\frac{x}{y} = \frac{2}{1}$.To find the value of $\frac{x^{2} - y^{2}}{x^{2} + y^{2}}$,we can

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$3:5$

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(A) Given the ratio $x : y = 2 : 1$,we can write this as $\frac{x}{y} = \frac{2}{1}$.To find the value of $\frac{x^{2} - y^{2}}{x^{2} + y^{2}}$,we can divide both the numerator and the denominator by $y^{2}$:$\frac{x^{2} - y^{2}}{x^{2} + y^{2}} = \frac{(\frac{x}{y})^{2} - 1}{(\frac{x}{y})^{2} + 1}$.Substituting the value $\frac{x}{y} = 2$:$\frac{2^{2} - 1}{2^{2} + 1} = \frac{4 - 1}{4 + 1} = \frac{3}{5}$.Therefore,the ratio is $3 : 5$.

If $x: y = 2: 1,$ then $(x^{2} - y^{2}) : (x^{2} + y^{2})$ is

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