If 40 % of a number is equal to two-thirds of | vedclass

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Question

(C) Let the first number be $x$ and the second number be $y$.According to the problem,$40 \%$ of $x = \frac{2}{3}$ of $y$.This can be written as: $0.4

Vedclass · Accepted Answer

$5: 3$

Vedclass · Answer

(C) Let the first number be $x$ and the second number be $y$.According to the problem,$40 \%$ of $x = \frac{2}{3}$ of $y$.This can be written as: $0.4x = \frac{2}{3}y$.To find the ratio $\frac{x}{y}$,rearrange the equation:$\frac{x}{y} = \frac{2}{3 	imes 0.4}$.Since $0.4 = \frac{4}{10} = \frac{2}{5}$,we substitute this into the equation:$\frac{x}{y} = \frac{2}{3 	imes (2/5)} = \frac{2}{6/5} = 2 	imes \frac{5}{6} = \frac{10}{6} = \frac{5}{3}$.Therefore,the ratio of the first number to the second number is $5: 3$.

If $40 \%$ of a number is equal to two-thirds of another number,what is the ratio of the first number to the second number?

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