If A travels to his school from his house at | vedclass

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(B) Let the distance between the house and the school be $x \, km$.Time taken at $3 \, km/h = \frac{x}{3} \, hours$.Time taken at $4 \, km/h = \frac{x

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$2$

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(B) Let the distance between the house and the school be $x \, km$.Time taken at $3 \, km/h = \frac{x}{3} \, hours$.Time taken at $4 \, km/h = \frac{x}{4} \, hours$.The difference in time between the two scenarios is $5 \, minutes$ late and $5 \, minutes$ early,which equals $10 \, minutes$ or $\frac{10}{60} = \frac{1}{6} \, hours$.According to the problem:$\frac{x}{3} - \frac{x}{4} = \frac{1}{6}$Taking the common denominator:$\frac{4x - 3x}{12} = \frac{1}{6}$$\frac{x}{12} = \frac{1}{6}$$x = \frac{12}{6} = 2 \, km$.Therefore,the distance is $2 \, km$.

If $A$ travels to his school from his house at the speed of $3 \, km/h$,he reaches the school $5 \, minutes$ late. If he travels at the speed of $4 \, km/h$,he reaches the school $5 \, minutes$ earlier than the scheduled time. The distance of his school from his house is (in $km$):

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