If $\frac{x}{y} = \frac{3}{4}$,then the value of $\left(\frac{6}{7} + \frac{y-x}{y+x}\right)$ equals:

  • A
    $\frac{5}{7}$
  • B
    $1 \frac{1}{7}$
  • C
    $1$
  • D
    $2$

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