If (frac{5}{9} text{ of } x) - (frac{2}{5} te | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given equation: $(\frac{5}{9} 	imes x) - (\frac{2}{5} 	imes \frac{9}{4}) = -\frac{4}{5}$Simplify the second term: $\frac{2}{5} 	imes \frac{9}{4

Vedclass · Accepted Answer

$0.18$

Vedclass · Answer

(A) Given equation: $(\frac{5}{9} 	imes x) - (\frac{2}{5} 	imes \frac{9}{4}) = -\frac{4}{5}$Simplify the second term: $\frac{2}{5} 	imes \frac{9}{4} = \frac{18}{20} = \frac{9}{10}$Substitute back into the equation: $\frac{5}{9}x - \frac{9}{10} = -\frac{4}{5}$Add $\frac{9}{10}$ to both sides: $\frac{5}{9}x = -\frac{4}{5} + \frac{9}{10}$Find a common denominator for the right side: $\frac{5}{9}x = -\frac{8}{10} + \frac{9}{10} = \frac{1}{10}$Solve for $x$: $x = \frac{1}{10} 	imes \frac{9}{5} = \frac{9}{50}$Convert to decimal: $x = 0.18$

If $(\frac{5}{9} \text{ of } x) - (\frac{2}{5} \text{ of } \frac{9}{4}) = -\frac{4}{5}$,then find $x$.

Similar Questions

The value of $(3+\sqrt{8})+\frac{1}{3-\sqrt{8}}-(6+4 \sqrt{2})$ is

If $1^{3}+2^{3}+\cdots+9^{3}=2025,$ then the value of $(0.11)^{3}+(0.22)^{3}+\cdots+(0.99)^{3}$ is close to

What least value should be added to $2505$ so that it becomes a perfect square?

The value of $\frac{3.157 \times 4126 \times 3.198}{63.972 \times 2835.121}$ is nearer to

$11.6 + 9.28 + 0.464 - 0.2828 + 0.07 = ?$

Vedclass Test Series

Exam Paper Generator

Online Exam Module