If sqrt{5} = 2.236,then what is the value of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given expression: $\frac{\sqrt{5}}{2} + \frac{5}{3 \sqrt{5}} - \sqrt{45}$First,simplify the terms:$\sqrt{45} = \sqrt{9 	imes 5} = 3 \sqrt{5}$$\fr

Vedclass · Accepted Answer

$-4.845$

Vedclass · Answer

(B) Given expression: $\frac{\sqrt{5}}{2} + \frac{5}{3 \sqrt{5}} - \sqrt{45}$First,simplify the terms:$\sqrt{45} = \sqrt{9 	imes 5} = 3 \sqrt{5}$$\frac{5}{3 \sqrt{5}} = \frac{\sqrt{5} 	imes \sqrt{5}}{3 \sqrt{5}} = \frac{\sqrt{5}}{3}$Substitute these into the expression:$\frac{\sqrt{5}}{2} + \frac{\sqrt{5}}{3} - 3 \sqrt{5}$Take $\sqrt{5}$ as a common factor:$\sqrt{5} \left( \frac{1}{2} + \frac{1}{3} - 3 ight) = \sqrt{5} \left( \frac{3 + 2 - 18}{6} ight) = \sqrt{5} \left( \frac{-13}{6} ight)$Substitute $\sqrt{5} = 2.236$:$2.236 	imes \left( \frac{-13}{6} ight) = 2.236 	imes (-2.1666...) = -4.8447... \approx -4.845$

If $\sqrt{5} = 2.236$,then what is the value of $\frac{\sqrt{5}}{2} + \frac{5}{3 \sqrt{5}} - \sqrt{45}$?

Similar Questions

When $\frac{1}{4}$ of a number is subtracted from $\frac{1}{3}$ of the same number,the remainder obtained is $12$. The number is:

$\frac{0.0203 \times 2.92}{0.0073 \times 14.5 \times 0.7} = ?$

$\frac{1}{3} + \frac{1}{2} + \frac{1}{x} = 4$. Then $x = ?$

Evaluate $\frac{8-[5-(-3+2)]+2}{|5-3|-|5-8|+3}$

If $a^{4}+a^{2} b^{2}+b^{4}=8$ and $a^{2}+a b+b^{2}=4,$ then the value of $a b$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module