If $p=99,$ then the value of $p(p^{2}+3p+3)$ is

What approximate value will come in place of the question mark $(?)$ in the given equation? (You are not expected to calculate the exact value)
$24.98^{2} \times \frac{16.02^{2}}{(7.98 \times 15.04)} \times 38.93 = 130 \times ?^{2}$

$0.002 \times 0.5 = ?$

$(1.06+0.04)^{2}-?=4 \times 1.06 \times 0.04$

$48 \div 12 \times \left( \frac{9}{8} \text{ of } \frac{4}{3} + \frac{3}{4} \text{ of } \frac{2}{3} \right) = ?$

$198.995 \times 12.005 + 16.25 \times 6.95 = ?$