If $4\,P(A) = 6\,P(B) = 10\,P(A \cap B) = 1,$ then $P\left( \frac{B}{A} \right) = $

$A$ man draws a card from a pack of $52$ playing cards,replaces it,and shuffles the pack. He continues this process until he gets a card of spade. The probability that he will fail the first two times is

$A$ fair coin is tossed $100$ times. The probability of getting tails an odd number of times is

$A$ card is drawn at random from a well-shuffled pack of $52$ cards. The probability of getting a two of hearts or a two of diamonds is:

For a biased die,the probabilities for different faces to turn up are given below:

$Face$	$1$	$2$	$3$	$4$	$5$	$6$
$Probability$	$0.1$	$0.32$	$0.21$	$0.15$	$0.05$	$0.17$

The die is tossed and you are told that either face $1$ or $2$ has turned up. Then the probability that it is face $1$ is:

$A$ card is drawn at random from a pack of cards. What is the probability that the drawn card is neither a heart nor a king?