If A and B are sets,then A cap (B - A) is | vedclass

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(A) By the definition of set difference,$B - A$ is the set of all elements that are in $B$ but not in $A$.Therefore,for any element $x \in (B - A)$,it

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$\phi$

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(A) By the definition of set difference,$B - A$ is the set of all elements that are in $B$ but not in $A$.Therefore,for any element $x \in (B - A)$,it is guaranteed that $x 
otin A$.Since $A \cap (B - A)$ represents the set of elements common to both $A$ and $(B - A)$,and there are no elements common to $A$ and $(B - A)$,the intersection must be the empty set.Thus,$A \cap (B - A) = \phi$.

If $A$ and $B$ are sets,then $A \cap (B - A)$ is

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