If sin theta + csc theta = 2,then sin^2 theta | vedclass

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Question

(C) Given that $\sin 	heta + \csc 	heta = 2$.Squaring both sides of the equation:$(\sin 	heta + \csc 	heta)^2 = 2^2$$\sin^2 	heta + \csc^2 	heta

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$2$

Vedclass · Answer

(C) Given that $\sin 	heta + \csc 	heta = 2$.Squaring both sides of the equation:$(\sin 	heta + \csc 	heta)^2 = 2^2$$\sin^2 	heta + \csc^2 	heta + 2 \sin 	heta \csc 	heta = 4$Since $\csc 	heta = \frac{1}{\sin 	heta}$,we have $\sin 	heta \csc 	heta = 1$.Substituting this value into the equation:$\sin^2 	heta + \csc^2 	heta + 2(1) = 4$$\sin^2 	heta + \csc^2 	heta + 2 = 4$$\sin^2 	heta + \csc^2 	heta = 4 - 2 = 2$.

If $\sin \theta + \csc \theta = 2$,then $\sin^2 \theta + \csc^2 \theta = $

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