If sin theta_1 + sin theta_2 + sin theta_3 = | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given that $\sin 	heta_1 + \sin 	heta_2 + \sin 	heta_3 = 3$.Since the maximum value of the sine function is $1$,this equation can only hold tru

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(D) Given that $\sin 	heta_1 + \sin 	heta_2 + \sin 	heta_3 = 3$.Since the maximum value of the sine function is $1$,this equation can only hold true if each term is equal to $1$.Therefore,$\sin 	heta_1 = 1$,$\sin 	heta_2 = 1$,and $\sin 	heta_3 = 1$.This implies that $	heta_1 = 	heta_2 = 	heta_3 = \frac{\pi}{2}$.Now,substituting these values into the expression $\cos 	heta_1 + \cos 	heta_2 + \cos 	heta_3$:$\cos(\frac{\pi}{2}) + \cos(\frac{\pi}{2}) + \cos(\frac{\pi}{2}) = 0 + 0 + 0 = 0$.

If $\sin \theta_1 + \sin \theta_2 + \sin \theta_3 = 3$,then $\cos \theta_1 + \cos \theta_2 + \cos \theta_3 = $

Similar Questions

If $\tan 20^{\circ} = k,$ then $\frac{\tan 250^{\circ} + \tan 340^{\circ}}{\tan 200^{\circ} - \tan 110^{\circ}} = $

If $\sin x + \cos x = \frac{1}{5},$ then $\tan 2x$ is

If $A, B, C$ are the angles of a triangle,then $\sin^2 A + \sin^2 B + \sin^2 C - 2\cos A \cos B \cos C = $

The value of $2(\sin^6 \theta + \cos^6 \theta) - 3(\sin^4 \theta + \cos^4 \theta) + 1$ is

Let $A, B, C$ be three angles such that $\sin A + \sin B + \sin C = 0$. Then,$\frac{\sin A \sin B \sin C}{\sin 3A + \sin 3B + \sin 3C}$ (wherever defined) is equal to:

Vedclass Test Series

Exam Paper Generator

Online Exam Module