If tan (A + B) = p and tan (A - B) = q, then | vedclass

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(C) We know that $2A = (A + B) + (A - B).$Taking the tangent on both sides,we get $	an 2A = 	an((A + B) + (A - B)).$Using the formula $	an(x + y) =

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$\frac{p + q}{1 - pq}$

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(C) We know that $2A = (A + B) + (A - B).$Taking the tangent on both sides,we get $	an 2A = 	an((A + B) + (A - B)).$Using the formula $	an(x + y) = \frac{	an x + 	an y}{1 - 	an x 	an y},$we substitute $x = (A + B)$ and $y = (A - B).$Thus,$	an 2A = \frac{	an(A + B) + 	an(A - B)}{1 - 	an(A + B)	an(A - B)}.$Substituting the given values $	an(A + B) = p$ and $	an(A - B) = q,$we get $	an 2A = \frac{p + q}{1 - pq}.$

If $\tan (A + B) = p$ and $\tan (A - B) = q,$ then the value of $\tan 2A$ in terms of $p$ and $q$ is

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