If 5.85 g of NaCl are dissolved in 90 g of | vedclass

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(D) The molar mass of $NaCl$ is $58.5 \ g/mol$. The number of moles of $NaCl$ is $n_{NaCl} = \frac{5.85 \ g}{58.5 \ g/mol} = 0.1 \ mol$.The molar mass

Vedclass · Accepted Answer

$0.0196$

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(D) The molar mass of $NaCl$ is $58.5 \ g/mol$. The number of moles of $NaCl$ is $n_{NaCl} = \frac{5.85 \ g}{58.5 \ g/mol} = 0.1 \ mol$.The molar mass of $H_2O$ is $18 \ g/mol$. The number of moles of $H_2O$ is $n_{H_2O} = \frac{90 \ g}{18 \ g/mol} = 5 \ mol$.The mole fraction of $NaCl$ is given by $\chi_{NaCl} = \frac{n_{NaCl}}{n_{NaCl} + n_{H_2O}} = \frac{0.1}{0.1 + 5} = \frac{0.1}{5.1} \approx 0.0196$.

If $5.85 \ g$ of $NaCl$ are dissolved in $90 \ g$ of water,the mole fraction of $NaCl$ is

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