If Delta ABC is right-angled at B,AB = 6 unit | vedclass

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(C) In the right-angled triangle $\Delta ABC$,the side $AB$ is opposite to the angle $\angle C = 30^{\circ}$,and $AC$ is the hypotenuse.Using the trig

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$12$

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(C) In the right-angled triangle $\Delta ABC$,the side $AB$ is opposite to the angle $\angle C = 30^{\circ}$,and $AC$ is the hypotenuse.Using the trigonometric ratio for sine:$\sin C = \frac{	ext{Opposite side}}{	ext{Hypotenuse}} = \frac{AB}{AC}$Given $\angle C = 30^{\circ}$ and $AB = 6$ units:$\sin 30^{\circ} = \frac{6}{AC}$Since $\sin 30^{\circ} = \frac{1}{2}$,we have:$\frac{1}{2} = \frac{6}{AC}$$AC = 6 	imes 2 = 12$ units.

If $\Delta ABC$ is right-angled at $B$,$AB = 6$ units,and $\angle C = 30^{\circ}$,then $AC$ is equal to (in units):

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