If A = {x : x = frac{n-1}{n+1}, n in W} and { | vedclass

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Question

(A) Given the set $A = \{x : x = \frac{n-1}{n+1},\ n \in W,\ n \le 10\}$.
Since $n \in W$ (whole numbers), the possible values for $n$ are:
$\{0,1,2

Vedclass · Accepted Answer

$0 \in A$

Vedclass · Answer

(A) Given the set $A = \{x : x = \frac{n-1}{n+1},\ n \in W,\ n \le 10\}$.
Since $n \in W$ (whole numbers), the possible values for $n$ are:
$\{0,1,2,3,4,5,6,7,8,9,10\}$
For $n = 0$:
$x = \frac{0-1}{0+1} = -1$
For $n = 1$:
$x = \frac{1-1}{1+1} = 0$
Since $1 \in W$ and $1 \le 10$, we get $x = 0$ is obtained.
Therefore, $0 \in A$ is a correct statement.

If $A = \{x : x = \frac{n-1}{n+1}, n \in W\}$ and $\{n \leq 10\}$,point out the correct statement from the following:

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