If 3^{x-2}=5 and log_{10} 2=0.30103, log_{10} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given $3^{x-2} = 5$.Taking $\log_{10}$ on both sides:$(x-2) \log_{10} 3 = \log_{10} 5$Since $\log_{10} 5 = \log_{10} (10/2) = \log_{10} 10 - \log_

Vedclass · Accepted Answer

$3 \frac{22187}{47710}$

Vedclass · Answer

(C) Given $3^{x-2} = 5$.Taking $\log_{10}$ on both sides:$(x-2) \log_{10} 3 = \log_{10} 5$Since $\log_{10} 5 = \log_{10} (10/2) = \log_{10} 10 - \log_{10} 2 = 1 - 0.30103 = 0.69897$.So,$(x-2) (0.4771) = 0.69897$.$x-2 = \frac{0.69897}{0.4771} = 1.465038...$$x = 2 + 1.465038 = 3.465038$.Calculating the fraction: $3 \frac{22187}{47710} = 3 + \frac{22187}{47710} \approx 3 + 0.465038 = 3.465038$.Thus,$x = 3 \frac{22187}{47710}$.

If $3^{x-2}=5$ and $\log_{10} 2=0.30103, \log_{10} 3=0.4771$,then $x=$

Similar Questions

If $a^{x}=b^{y}=c^{z}=d^{w},$ then $\log _{a}(b c d)=$

If $\log _{a}(a b)=x,$ then $\log _{b}(a b)$ is

$5^{\sqrt{\log _{5} 7}} - 7^{\sqrt{\log _{7} 5}}$

$\log _{10} \tan 40^{\circ} \cdot \log _{10} \tan 41^{\circ} \cdots \log _{10} \tan 50^{\circ} = ?$

$2 \log _{10} 5 + \log _{10} 8 - \frac{1}{2} \log _{10} 4 = ?$

Vedclass Test Series

Exam Paper Generator

Online Exam Module