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(C) The dissociation of $Na_2SO_4$ is represented as: $Na_2SO_4 \rightleftharpoons 2Na^{+} + SO_4^{2-}$Initial moles: $1 \quad 0 \quad 0$Moles at equi

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$1 + 2\alpha$

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(C) The dissociation of $Na_2SO_4$ is represented as: $Na_2SO_4 \rightleftharpoons 2Na^{+} + SO_4^{2-}$Initial moles: $1 \quad 0 \quad 0$Moles at equilibrium: $1 - \alpha \quad 2\alpha \quad \alpha$Total moles at equilibrium = $(1 - \alpha) + 2\alpha + \alpha = 1 + 2\alpha$The Van't Hoff factor $(i)$ is defined as the ratio of the total number of particles after dissociation to the initial number of particles.$i = \frac{1 + 2\alpha}{1} = 1 + 2\alpha$

If $\alpha$ is the degree of dissociation of $Na_2SO_4$,the Van't Hoff factor $(i)$ used for calculating the molecular mass is

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