If cos A = frac{4}{5},then the value of tan A | vedclass

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(A) Given,$\cos A = \frac{4}{5}$.We know that $\sin^2 A + \cos^2 A = 1$,so $\sin A = \sqrt{1 - \cos^2 A}$.Substituting the value of $\cos A$:$\sin A =

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$\frac{3}{4}$

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(A) Given,$\cos A = \frac{4}{5}$.We know that $\sin^2 A + \cos^2 A = 1$,so $\sin A = \sqrt{1 - \cos^2 A}$.Substituting the value of $\cos A$:$\sin A = \sqrt{1 - (\frac{4}{5})^2} = \sqrt{1 - \frac{16}{25}} = \sqrt{\frac{25 - 16}{25}} = \sqrt{\frac{9}{25}} = \frac{3}{5}$.Now,$	an A = \frac{\sin A}{\cos A}$.Substituting the values of $\sin A$ and $\cos A$:$	an A = \frac{3/5}{4/5} = \frac{3}{4}$.Thus,the value of $	an A$ is $\frac{3}{4}$.

If $\cos A = \frac{4}{5}$,then the value of $\tan A$ is

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