If p(x) = x^{2} - 4x + 3,then find the value | vedclass

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(B) Given the polynomial $p(x) = x^{2} - 4x + 3$.First,calculate $p(2)$:$p(2) = (2)^{2} - 4(2) + 3 = 4 - 8 + 3 = -1$.Next,calculate $p(-1)$:$p(-1) = (

Vedclass · Accepted Answer

$-31$

Vedclass · Answer

(B) Given the polynomial $p(x) = x^{2} - 4x + 3$.First,calculate $p(2)$:$p(2) = (2)^{2} - 4(2) + 3 = 4 - 8 + 3 = -1$.Next,calculate $p(-1)$:$p(-1) = (-1)^{2} - 4(-1) + 3 = 1 + 4 + 3 = 8$.Then,calculate $p(1/2)$:$p(1/2) = (1/2)^{2} - 4(1/2) + 3 = 1/4 - 2 + 3 = 1/4 + 1 = 5/4$.Finally,substitute these values into the expression $p(2) - p(-1) + p(1/2)$:$-1 - 8 + 5/4 = -9 + 5/4 = (-36 + 5) / 4 = -31/4$.

If $p(x) = x^{2} - 4x + 3$,then find the value of $p(2) - p(-1) + p(1/2)$. (in $/4$)

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