If x^{2}-8x-20=(x+a)(x+b), then ab=ldots ldot | vedclass

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(B) Given the quadratic expression $x^{2}-8x-20 = (x+a)(x+b)$.Expanding the right side,we get $(x+a)(x+b) = x^{2} + (a+b)x + ab$.Comparing this with t

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$-20$

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(B) Given the quadratic expression $x^{2}-8x-20 = (x+a)(x+b)$.Expanding the right side,we get $(x+a)(x+b) = x^{2} + (a+b)x + ab$.Comparing this with the given expression $x^{2}-8x-20$,we equate the constant terms.The constant term on the left side is $-20$.The constant term on the right side is $ab$.Therefore,$ab = -20$.

If $x^{2}-8x-20=(x+a)(x+b),$ then $ab=\ldots \ldots \ldots$

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