If 3 theta is the measure of an acute angle a | vedclass

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(C) Given that $\sin 3 	heta = \cos (	heta - 26^{\circ})$.We know that $\sin A = \cos (90^{\circ} - A)$.Therefore,$\cos (90^{\circ} - 3 	heta) = \c

Vedclass · Accepted Answer

$29$

Vedclass · Answer

(C) Given that $\sin 3 	heta = \cos (	heta - 26^{\circ})$.We know that $\sin A = \cos (90^{\circ} - A)$.Therefore,$\cos (90^{\circ} - 3 	heta) = \cos (	heta - 26^{\circ})$.Equating the angles,we get $90^{\circ} - 3 	heta = 	heta - 26^{\circ}$.Rearranging the terms,$90^{\circ} + 26^{\circ} = 	heta + 3 	heta$.$116^{\circ} = 4 	heta$.$	heta = \frac{116^{\circ}}{4} = 29^{\circ}$.Thus,the value of $	heta$ is $29^{\circ}$.

If $3 \theta$ is the measure of an acute angle and $\sin 3 \theta = \cos (\theta - 26^{\circ})$,then the value of $\theta$ is $\ldots \ldots \ldots \ldots$ (in $^{\circ}$)

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