If $M = 72$ and $\bar{x} = 70$,then $Z = \ldots \ldots \ldots \ldots$
- A$74$
- B$76$
- C$68$
- D$75$
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Similar Questions
For a given frequency distribution,$\bar{x}=54.3, \Sigma f_{i} u_{i}=2, n=25$ and $c=10$. Then the assumed mean $A = \dots$
Medium
View SolutionConsider the data:
Class $65-85$ $85-105$ $105-125$ $125-145$ $145-165$ $165-185$ $185-205$ Frequency $4$ $5$ $13$ $20$ $14$ $7$ $4$
The difference between the upper limit of the median class and the lower limit of the modal class is:
| Class | $65-85$ | $85-105$ | $105-125$ | $125-145$ | $145-165$ | $165-185$ | $185-205$ |
| Frequency | $4$ | $5$ | $13$ | $20$ | $14$ | $7$ | $4$ |
The difference between the upper limit of the median class and the lower limit of the modal class is:
Medium
View Solution$\frac{Z-M}{M-\bar{x}}=\ldots \ldots \ldots \ldots$
Easy
View SolutionFind the mean of the following data:
Class $200-299$ $300-399$ $400-499$ $500-599$ $600-699$ $700-799$ $800-899$ Frequency $3$ $61$ $118$ $139$ $126$ $151$ $2$
| Class | $200-299$ | $300-399$ | $400-499$ | $500-599$ | $600-699$ | $700-799$ | $800-899$ |
| Frequency | $3$ | $61$ | $118$ | $139$ | $126$ | $151$ | $2$ |
Medium
View SolutionThe mean of $15$ observations is $16$. If $2$ is added to each observation and then each result is divided by $3$,the new mean is:
Medium
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