If r represents the radius of the orbit of a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) For a satellite of mass $m$ to revolve in a circular orbit of radius $r$ around a planet of mass $M$,the gravitational force provides the necessar

Vedclass · Accepted Answer

$v^2 = \frac{GM}{r}$

Vedclass · Answer

(D) For a satellite of mass $m$ to revolve in a circular orbit of radius $r$ around a planet of mass $M$,the gravitational force provides the necessary centripetal force.The gravitational force is given by $F_g = \frac{GMm}{r^2}$.The centripetal force required for circular motion is $F_c = \frac{mv^2}{r}$.Equating the two forces:$\frac{mv^2}{r} = \frac{GMm}{r^2}$.Canceling $m$ from both sides and multiplying by $r$:$v^2 = \frac{GM}{r}$.Thus,the correct expression is $v^2 = \frac{GM}{r}$.

If $r$ represents the radius of the orbit of a satellite of mass $m$ moving around a planet of mass $M$,the velocity of the satellite is given by

Similar Questions

The time period of a geostationary satellite is

The time period of a $1500 \,kg$ satellite is equal to the time period of rotation of the earth. The altitude of the satellite is nearly

The mass density of a spherical galaxy varies as $\frac{K}{r}$ over a large distance $r$ from its centre. In that region,a small star is in a circular orbit of radius $R$. Then the period of revolution,$T$ depends on $R$ as

The Earth moves around the Sun in an elliptical orbit as shown in the figure. The ratio $OA/OB = x$. The ratio of the speed of the Earth at $B$ to that at $A$ is nearly

If the horizontal velocity given to a satellite is greater than critical velocity but less than the escape velocity at the height,then the satellite will

Vedclass Test Series

Exam Paper Generator

Online Exam Module