If 4.8 text{ A} current is passed through an | vedclass

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(C) The formula for electric current $(I)$ is given by $I = \frac{Q}{t}$,where $Q$ is the total charge and $t$ is the time.Since $Q = ne$,where $n$ is

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$3 	imes 10^{19}$

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(C) The formula for electric current $(I)$ is given by $I = \frac{Q}{t}$,where $Q$ is the total charge and $t$ is the time.Since $Q = ne$,where $n$ is the number of electrons and $e$ is the elementary charge $(e \approx 1.6 	imes 10^{-19} 	ext{ C})$,the formula becomes $I = \frac{ne}{t}$.Given: $I = 4.8 	ext{ A}$,$t = 1 	ext{ s}$,and $e = 1.6 	imes 10^{-19} 	ext{ C}$.Rearranging for $n$: $n = \frac{I 	imes t}{e}$.Substituting the values: $n = \frac{4.8 	imes 1}{1.6 	imes 10^{-19}}$.$n = 3 	imes 10^{19}$ electrons.Therefore,the number of electrons passing through the appliance is $3 	imes 10^{19}$.

If $4.8 \text{ A}$ current is passed through an electrical appliance,then the number of electrons passing through it in $1 \text{ second}$ will be $......$

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