If G is the universal gravitational constant | vedclass

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Question

(A) The dimensional formula for the universal gravitational constant $G$ is $[M^{-1} L^3 T^{-2}]$.The dimensional formula for the acceleration due to

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$[M^{-1} L^2]$

Vedclass · Answer

(A) The dimensional formula for the universal gravitational constant $G$ is $[M^{-1} L^3 T^{-2}]$.The dimensional formula for the acceleration due to gravity $g$ is $[L T^{-2}]$.Now,calculate the dimensions of the ratio $\frac{G}{g}$:$\frac{G}{g} = \frac{[M^{-1} L^3 T^{-2}]}{[L T^{-2}]}$$= [M^{-1} L^{3-1} T^{-2 - (-2)}]$$= [M^{-1} L^2 T^0]$$= [M^{-1} L^2]$Therefore,the correct option is $A$.

If $G$ is the universal gravitational constant and $g$ is the acceleration due to gravity,then the dimensions of $\frac{G}{g}$ will be ...................

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