If theta is the angle between the velocity ve | vedclass

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(C) In non-uniform circular motion,the total acceleration $\vec{a}$ is the vector sum of the centripetal acceleration $\vec{a}_c$ and the tangential a

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$90^{\circ} < 	heta < 180^{\circ}$

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(C) In non-uniform circular motion,the total acceleration $\vec{a}$ is the vector sum of the centripetal acceleration $\vec{a}_c$ and the tangential acceleration $\vec{a}_T$,i.e.,$\vec{a} = \vec{a}_c + \vec{a}_T$.$1$. The centripetal acceleration $\vec{a}_c$ is always directed towards the center of the circle,making an angle of $90^{\circ}$ with the velocity vector $\vec{v}$.$2$. The tangential acceleration $\vec{a}_T$ acts along the tangent. Since the speed is decreasing,$\vec{a}_T$ is directed opposite to the velocity vector $\vec{v}$,making an angle of $180^{\circ}$ with it.$3$. The resultant acceleration $\vec{a}$ lies between the directions of $\vec{a}_c$ and $\vec{a}_T$. Therefore,the angle $	heta$ between the velocity $\vec{v}$ and the total acceleration $\vec{a}$ must be greater than $90^{\circ}$ (due to $\vec{a}_c$) and less than $180^{\circ}$ (due to $\vec{a}_T$).Thus,$90^{\circ} < 	heta < 180^{\circ}$.

If $\theta$ is the angle between the velocity vector $\vec{v}$ and the acceleration vector $\vec{a}$ of a particle moving on a circular path with decreasing speed,then .........

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