If $(20)^{19} + 2(21)(20)^{18} + 3(21)^2(20)^{17} + \ldots + 20(21)^{19} = k (20)^{19}$,then $k$ is equal to

  • A
    $200$
  • B
    $300$
  • C
    $400$
  • D
    $100$

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