If $A$ and $B$ are not disjoint sets,then $n(A \cup B)$ is equal to
- A$n(A) + n(B)$
- B$n(A) + n(B) - n(A \cap B)$
- C$n(A) + n(B) + n(A \cap B)$
- D$n(A) \times n(B)$
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