If $917 \mathring A$ is the lowest wavelength of the Lyman series,then the lowest wavelength of the Balmer series will be .......$\mathring A$.

The second line of the Balmer series has a wavelength of $4861 Å$. The wavelength of the first line of the Balmer series is: (in $Å$)

When an electron makes a transition from $n=4$ to $n=2$,the emitted line spectrum will be:

The third line of the Balmer series in the emission spectrum of the hydrogen atom is due to the transition of an electron from the:

$A$ hydrogen atom is excited from the ground state to another state with a principal quantum number equal to $4$. The number of spectral lines in the emission spectra will be:

The stopping potential for the photoelectrons emitted from a metal surface of work function $1.7 \ eV$ is $10.4 \ V$. Identify the energy levels corresponding to the transitions in a hydrogen atom which will result in the emission of a wavelength equal to that of the incident radiation for the above photoelectric effect.