If text{HCF}(65, 117) = 65m - 117,then find t | vedclass

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(B) First,find the prime factorization of $65$ and $117$.$65 = 5 	imes 13$$117 = 9 	imes 13 = 3^2 	imes 13$The $	ext{HCF}(65, 117)$ is the common

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$2$

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(B) First,find the prime factorization of $65$ and $117$.$65 = 5 	imes 13$$117 = 9 	imes 13 = 3^2 	imes 13$The $	ext{HCF}(65, 117)$ is the common factor with the lowest power,which is $13$.Given the equation: $	ext{HCF}(65, 117) = 65m - 117$Substitute the value of $	ext{HCF}$:$13 = 65m - 117$Add $117$ to both sides:$13 + 117 = 65m$$130 = 65m$Divide by $65$:$m = \frac{130}{65} = 2$Thus,the value of $m$ is $2$.

If $\text{HCF}(65, 117) = 65m - 117$,then find the value of $m$.

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