If p(x) = 2x^4 - 3x^3 + 7x + 5,then the value | vedclass

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(D) To find the value of $p(-2)$,substitute $x = -2$ into the given polynomial $p(x) = 2x^4 - 3x^3 + 7x + 5$.$p(-2) = 2(-2)^4 - 3(-2)^3 + 7(-2) + 5$Ca

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$47$

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(D) To find the value of $p(-2)$,substitute $x = -2$ into the given polynomial $p(x) = 2x^4 - 3x^3 + 7x + 5$.$p(-2) = 2(-2)^4 - 3(-2)^3 + 7(-2) + 5$Calculate the powers:$(-2)^4 = 16$$(-2)^3 = -8$Substitute these values back into the expression:$p(-2) = 2(16) - 3(-8) + 7(-2) + 5$$p(-2) = 32 + 24 - 14 + 5$$p(-2) = 56 - 14 + 5$$p(-2) = 42 + 5$$p(-2) = 47$

$Q.1.$ $HCF$ of $25$ and $10$	$A. 5$
$Q.2.$ $LCM$ of $17$ and $11$	$B. 187$

If $p(x) = 2x^4 - 3x^3 + 7x + 5$,then the value of $p(-2)$ is:

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