If a and b are odd integers,then the roots of | vedclass

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(A) Given the quadratic equation $2ax^2 + (2a + b)x + b = 0$,where $a 
e 0$.The discriminant $D$ is given by $D = B^2 - 4AC$.Substituting the coeffic

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Rational

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(A) Given the quadratic equation $2ax^2 + (2a + b)x + b = 0$,where $a 
e 0$.The discriminant $D$ is given by $D = B^2 - 4AC$.Substituting the coefficients $A = 2a$,$B = (2a + b)$,and $C = b$:$D = (2a + b)^2 - 4(2a)(b)$$D = 4a^2 + 4ab + b^2 - 8ab$$D = 4a^2 - 4ab + b^2$$D = (2a - b)^2$.Since $a$ and $b$ are integers,$(2a - b)^2$ is a perfect square of an integer.For a quadratic equation with rational coefficients,if the discriminant is a perfect square,the roots are rational.

If $a$ and $b$ are odd integers,then the roots of the equation $2ax^2 + (2a + b)x + b = 0, a \ne 0,$ will be

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