If $K_{sp}$ is the solubility product of $Al(OH)_3$,its solubility is expressed by the formula:
- A$\sqrt[3]{\frac{4}{K_{sp}}}$
- B$\sqrt[3]{\frac{K_{sp}}{4}}$
- C$\sqrt[4]{\frac{K_{sp}}{27}}$
- D$\sqrt[4]{K_{sp} \times 27}$
Explore More
Similar Questions
The solubility of $I_2$ increases in water in the presence of
Easy
View SolutionThe solubility of $CaF_2$ in a solution of $0.1 \ M \ Ca(NO_3)_2$ is.
Medium
View SolutionThe solubility of $CaCO_3$ is $7 \times 10^{-5} \ mol \ dm^{-3}$ at $25^{\circ} C$. What is its solubility product at same temperature?
The solubility products $(K_{sp})$ of three sparingly soluble salts $M_2X$,$MX$,and $MX_3$ are identical. What will be the order of their solubilities $(s)$?
Medium
View SolutionIf the solubility products of $AgCl$ and $AgBr$ are $1.0 \times 10^{-10}$ and $3.5 \times 10^{-13}$ respectively,then the relation between the solubilities (denoted by the symbol $S$) of these salts can correctly be represented as:
Difficult
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo