If $f(x) = \frac{x}{2x+1}$ and $g(x) = \frac{x}{x+1}$,then $(f \circ g)(x) = $

  • A
    $\frac{2x-1}{x+1}$
  • B
    $\frac{x}{3x+1}$
  • C
    $\frac{x+1}{x+2}$
  • D
    $\frac{x-1}{2x+1}$

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