If A = begin{bmatrix} 1 & 2 & 3 -1 & 1 & 2 | vedclass

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(B) We know the property of matrices that $A(\operatorname{adj} A) = |A| I$,where $|A|$ is the determinant of matrix $A$ and $I$ is the identity matri

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$\begin{bmatrix} 3 & 0 & 0 \ 0 & 3 & 0 \ 0 & 0 & 3 \end{bmatrix}$

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(B) We know the property of matrices that $A(\operatorname{adj} A) = |A| I$,where $|A|$ is the determinant of matrix $A$ and $I$ is the identity matrix of the same order.First,calculate the determinant of $A$:$|A| = 1(1 	imes 4 - 2 	imes 2) - 2(-1 	imes 4 - 2 	imes 1) + 3(-1 	imes 2 - 1 	imes 1)$$|A| = 1(4 - 4) - 2(-4 - 2) + 3(-2 - 1)$$|A| = 1(0) - 2(-6) + 3(-3)$$|A| = 0 + 12 - 9 = 3$Now,substitute $|A|$ into the formula:$A(\operatorname{adj} A) = 3 	imes \begin{bmatrix} 1 & 0 & 0 \ 0 & 1 & 0 \ 0 & 0 & 1 \end{bmatrix} = \begin{bmatrix} 3 & 0 & 0 \ 0 & 3 & 0 \ 0 & 0 & 3 \end{bmatrix}$.

If $A = \begin{bmatrix} 1 & 2 & 3 \\ -1 & 1 & 2 \\ 1 & 2 & 4 \end{bmatrix}$,then $A(\operatorname{adj} A) = $

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