If $X \sim B(4, p)$ and $P(X=0)=\frac{16}{81}$,then $P(X=4)=$

  • A
    $\frac{1}{81}$
  • B
    $\frac{1}{16}$
  • C
    $\frac{1}{8}$
  • D
    $\frac{1}{27}$

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